VII. CONGRUENT LINES IN A TRIANGLE 55 x y Figure 51 Figure 52 and N be the midpoints of BG and CG. Segment MN , which joins the midpoints of two sides of triangle BCG, is parallel to BC and equal to half of it. But EF is parallel to BC and equal to half of it. This means that EF MN is a parallelogram, whose diagonals divide each other in half. Therefore EG = GM = MB and F G = GN = NC. Thus median BE passes through the point situated at one third the length of CF . But the same reasoning can also be applied to show that the median AD passes through the same point. The thereom is proved. Remark. The point where the medians meet is also called the center of mass of the triangle. The reason for this name is given in the study of mechanics.

Purchased from American Mathematical Society for the exclusive use of nofirst nolast (email unknown) Copyright 2008 American Mathematical Society. Duplication prohibited. Please report unauthorized use to cust-serv@ams.org. Thank You! Your purchase supports the AMS' mission, programs, and services for the mathematical community.